How Does the Fuse Burn When Short Circuit is Occur ?

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We might notice, when the electrical short circuit occur in our home,Suddenly the fuse in our home gets burn itself.......
Whenever have you thought about how it gets burn?,,,,,,
The most of the answers might be 'No'.... Right ?
Here, I explain how it happens.

What is Electric Voltage ?

    Voltage is a force to flow a current through a conductor....

What is Electric Current ?

    Current is the flow of electric charge through a conductor...

Simply, think a water pipe, In the pipe voltage is the speed of water flowing through the pipe and current is the amount of water flow through the pipe.

Now, Come to resistance....

What is electric resistance ?

    resistance is a opposing force to current flowing through the conductor.

What is Electric Fuse ?

  Fuse is a weakest connection in a circuit. It basically design as weakest part because when a fault occur in a circuit, The fuse should get burned itself. By this process the circuit will be disconnected.

Always resistance try to stop the current flow......

Now come to matter...

How Does the Fuse Burn When Short Circuit Occur ?

  In a simple house, The fuse is designed to flow the current below 32 Amperes. If the current is increases above it, The fuse will automatically burn.

Every electric devices or machines having a specified resistance amount..... For example my music amplifier having around 240 amount of resistance...

The working voltage of the amplifier is 230 V.

Then,

lets calculate the current needed to this amplifier..

The formula is ,       Current (I) = Voltage (V) / Resistance( R)

We know,  The working voltage is 230V and Resistance of the device is 240 Ohm.

                                               I = 230 / 240  = 0.958333333 A, right ?
Now, I want use 33 Amplifiers to burn the fuse ?
Answer is yes, But there is a another simple way to burn the fuse................

Use a 1 meter copper wire to connect the two terminals of the power supply (Short Circuit).....

The resistance of the copper wire (For 100 cm ) is just 1.72 x 10^-8

Conductors with Resistance

This time lets calculate the amount of current....

                                               I= 230 / 1.72 x 10^-8 =  1329.2093 A... Wow!!!!!

Just after you short circuit the circuit using 100 cm copper wire, the current will flow 1329.2093 A amount of current through the circuit. But the fuse only allow 32 A to flow....

What will happen ?
     The fuse will burn, right ?.

That's all.....

Feel free to command , If you have any doubts......

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